Rust code uses snake case as the conventional style for function and variable names. In snake case, all letters are lowercase and underscores separate words. Here’s a program that contains an example function definition:

    Filename: src/main.rs

    Function definitions in Rust start with fn and have a set of parentheses after the function name. The curly brackets tell the compiler where the function body begins and ends.

    We can call any function we’ve defined by entering its name followed by a set of parentheses. Because another_function is defined in the program, it can be called from inside the main function. Note that we defined another_function after the main function in the source code; we could have defined it before as well. Rust doesn’t care where you define your functions, only that they’re defined somewhere.

    Let’s start a new binary project named functions to explore functions further. Place the another_function example in src/main.rs and run it. You should see the following output:

    $ cargo run Compiling functions v0.1.0 (file:///projects/functions) Finished dev [unoptimized + debuginfo] target(s) in 0.28s Running `target/debug/functions` Hello, world! Another function.

    The lines execute in the order in which they appear in the main function. First, the “Hello, world!” message prints, and then another_function is called and its message is printed.

    Functions can also be defined to have parameters, which are special variables that are part of a function’s signature. When a function has parameters, you can provide it with concrete values for those parameters. Technically, the concrete values are called arguments, but in casual conversation, people tend to use the words parameter and argument interchangeably for either the variables in a function’s definition or the concrete values passed in when you call a function.

    The following rewritten version of another_function shows what parameters look like in Rust:

    Filename: src/main.rs

    1. fn main() {
    2.     another_function(5);
    3. }
    5. fn another_function(x: i32) {
    6.     println!("The value of x is: {}", x);

    Try running this program; you should get the following output:

    $ cargo run Compiling functions v0.1.0 (file:///projects/functions) Finished dev [unoptimized + debuginfo] target(s) in 1.21s Running `target/debug/functions` The value of x is: 5

    The declaration of another_function has one parameter named x. The type of x is specified as i32. When 5 is passed to another_function, the println! macro puts 5 where the pair of curly brackets were in the format string.

    In function signatures, you must declare the type of each parameter. This is a deliberate decision in Rust’s design: requiring type annotations in function definitions means the compiler almost never needs you to use them elsewhere in the code to figure out what you mean.

    When you want a function to have multiple parameters, separate the parameter declarations with commas, like this:

    Filename: src/main.rs

    Let’s try running this code. Replace the program currently in your functions project’s src/main.rs file with the preceding example and run it using cargo run:

    $ cargo run Compiling functions v0.1.0 (file:///projects/functions) Finished dev [unoptimized + debuginfo] target(s) in 0.31s Running `target/debug/functions` The value of x is: 5 The value of y is: 6

    Because we called the function with 5 as the value for x and is passed as the value for y, the two strings are printed with these values.

    Function bodies are made up of a series of statements optionally ending in an expression. So far, we’ve only covered functions without an ending expression, but you have seen an expression as part of a statement. Because Rust is an expression-based language, this is an important distinction to understand. Other languages don’t have the same distinctions, so let’s look at what statements and expressions are and how their differences affect the bodies of functions.

    We’ve actually already used statements and expressions. Statements are instructions that perform some action and do not return a value. Expressions evaluate to a resulting value. Let’s look at some examples.

    Creating a variable and assigning a value to it with the let keyword is a statement. In Listing 3-1, let y = 6; is a statement.

    Filename: src/main.rs

    1. fn main() {
    2.     let y = 6;
    3. }

    Listing 3-1: A main function declaration containing one statement

    Function definitions are also statements; the entire preceding example is a statement in itself.

    Statements do not return values. Therefore, you can’t assign a let statement to another variable, as the following code tries to do; you’ll get an error:

    Filename: src/main.rs

    fn main() { let x = (let y = 6); }

    When you run this program, the error you’ll get looks like this:

    $ cargo run Compiling functions v0.1.0 (file:///projects/functions) error[E0658]: `let` expressions in this position are experimental --> src/main.rs:2:14 | 2 | let x = (let y = 6); | ^^^^^^^^^ | = note: see issue #53667 <https://github.com/rust-lang/rust/issues/53667> for more information = help: you can write `matches!(<expr>, <pattern>)` instead of `let <pattern> = <expr>` error: expected expression, found statement (`let`) --> src/main.rs:2:14 | 2 | let x = (let y = 6); | ^^^^^^^^^ | = note: variable declaration using `let` is a statement warning: unnecessary parentheses around assigned value --> src/main.rs:2:13 | 2 | let x = (let y = 6); | ^^^^^^^^^^^ help: remove these parentheses | = note: `#[warn(unused_parens)]` on by default error: aborting due to 2 previous errors; 1 warning emitted For more information about this error, try `rustc --explain E0658`. error: could not compile `functions` To learn more, run the command again with --verbose.

    The let y = 6 statement does not return a value, so there isn’t anything for x to bind to. This is different from what happens in other languages, such as C and Ruby, where the assignment returns the value of the assignment. In those languages, you can write x = y = 6 and have both x and y have the value 6; that is not the case in Rust.

    Expressions evaluate to something and make up most of the rest of the code that you’ll write in Rust. Consider a simple math operation, such as 5 + 6, which is an expression that evaluates to the value 11. Expressions can be part of statements: in Listing 3-1, the 6 in the statement let y = 6; is an expression that evaluates to the value 6. Calling a function is an expression. Calling a macro is an expression. The block that we use to create new scopes, {}, is an expression, for example:

    This expression:

    { let x = 3; x + 1 }

    is a block that, in this case, evaluates to 4. That value gets bound to y as part of the let statement. Note the x + 1 line without a semicolon at the end, which is unlike most of the lines you’ve seen so far. Expressions do not include ending semicolons. If you add a semicolon to the end of an expression, you turn it into a statement, which will then not return a value. Keep this in mind as you explore function return values and expressions next.

    Functions can return values to the code that calls them. We don’t name return values, but we do declare their type after an arrow (->). In Rust, the return value of the function is synonymous with the value of the final expression in the block of the body of a function. You can return early from a function by using the return keyword and specifying a value, but most functions return the last expression implicitly. Here’s an example of a function that returns a value:

    Filename: src/main.rs

    1. fn five() -> i32 {
    2.     5
    3. }
    5. fn main() {
    6.     let x = five();
    7.     println!("The value of x is: {}", x);
    8. }

    There are no function calls, macros, or even let statements in the five function—just the number 5 by itself. That’s a perfectly valid function in Rust. Note that the function’s return type is specified too, as -> i32. Try running this code; the output should look like this:

    $ cargo run Compiling functions v0.1.0 (file:///projects/functions) Finished dev [unoptimized + debuginfo] target(s) in 0.30s Running `target/debug/functions` The value of x is: 5

    The 5 in five is the function’s return value, which is why the return type is i32. Let’s examine this in more detail. There are two important bits: first, the line let x = five(); shows that we’re using the return value of a function to initialize a variable. Because the function five returns a 5, that line is the same as the following:

    Second, the five function has no parameters and defines the type of the return value, but the body of the function is a lonely 5 with no semicolon because it’s an expression whose value we want to return.

    Let’s look at another example:

    Filename: src/main.rs

    1. fn main() {
    2.     let x = plus_one(5);
    4.     println!("The value of x is: {}", x);
    5. }
    7. fn plus_one(x: i32) -> i32 {
    8. }

    Running this code will print The value of x is: 6. But if we place a semicolon at the end of the line containing x + 1, changing it from an expression to a statement, we’ll get an error.

    Filename: src/main.rs

    fn main() { let x = plus_one(5); println!("The value of x is: {}", x); } fn plus_one(x: i32) -> i32 { x + 1; }

    Compiling this code produces an error, as follows:

    $ cargo run Compiling functions v0.1.0 (file:///projects/functions) error[E0308]: mismatched types --> src/main.rs:7:24 | 7 | fn plus_one(x: i32) -> i32 { | -------- ^^^ expected `i32`, found `()` | | | implicitly returns `()` as its body has no tail or `return` expression 8 | x + 1; | - help: consider removing this semicolon error: aborting due to previous error For more information about this error, try `rustc --explain E0308`. error: could not compile `functions` To learn more, run the command again with --verbose.