Splitting the computation in your program into multiple threads to run multiple tasks at the same time can improve performance, but it also adds complexity. Because threads can run simultaneously, there’s no inherent guarantee about the order in which parts of your code on different threads will run. This can lead to problems, such as:
- Race conditions, where threads are accessing data or resources in an inconsistent order
- Deadlocks, where two threads are waiting for each other, preventing both threads from continuing
- Bugs that happen only in certain situations and are hard to reproduce and fix reliably
Rust attempts to mitigate the negative effects of using threads, but programming in a multithreaded context still takes careful thought and requires a code structure that is different from that in programs running in a single thread.
Programming languages implement threads in a few different ways, and many operating systems provide an API the language can call for creating new threads. The Rust standard library uses a 1:1 model of thread implementation, whereby a program uses one operating system thread per one language thread. There are crates that implement other models of threading that make different tradeoffs to the 1:1 model.
To create a new thread, we call the thread::spawn
function and pass it a closure (we talked about closures in Chapter 13) containing the code we want to run in the new thread. The example in Listing 16-1 prints some text from a main thread and other text from a new thread:
Filename: src/main.rs
Listing 16-1: Creating a new thread to print one thing while the main thread prints something else
Note that when the main thread of a Rust program completes, all spawned threads are shut down, whether or not they have finished running. The output from this program might be a little different every time, but it will look similar to the following:
hi number 1 from the main thread!
hi number 1 from the spawned thread!
hi number 2 from the main thread!
hi number 2 from the spawned thread!
hi number 3 from the main thread!
hi number 3 from the spawned thread!
hi number 4 from the main thread!
hi number 4 from the spawned thread!
hi number 5 from the spawned thread!
The calls to thread::sleep
force a thread to stop its execution for a short duration, allowing a different thread to run. The threads will probably take turns, but that isn’t guaranteed: it depends on how your operating system schedules the threads. In this run, the main thread printed first, even though the print statement from the spawned thread appears first in the code. And even though we told the spawned thread to print until i
is 9, it only got to 5 before the main thread shut down.
If you run this code and only see output from the main thread, or don’t see any overlap, try increasing the numbers in the ranges to create more opportunities for the operating system to switch between the threads.
The code in Listing 16-1 not only stops the spawned thread prematurely most of the time due to the main thread ending, but because there is no guarantee on the order in which threads run, we also can’t guarantee that the spawned thread will get to run at all!
We can fix the problem of the spawned thread not running or ending prematurely by saving the return value of thread::spawn
in a variable. The return type of thread::spawn
is JoinHandle
. A JoinHandle
is an owned value that, when we call the join
method on it, will wait for its thread to finish. Listing 16-2 shows how to use the JoinHandle
of the thread we created in Listing 16-1 and call join
to make sure the spawned thread finishes before main
exits:
use std::thread;
use std::time::Duration;
fn main() {
let handle = thread::spawn(|| {
for i in 1..10 {
println!("hi number {} from the spawned thread!", i);
thread::sleep(Duration::from_millis(1));
}
});
for i in 1..5 {
println!("hi number {} from the main thread!", i);
thread::sleep(Duration::from_millis(1));
}
handle.join().unwrap();
}
Listing 16-2: Saving a JoinHandle
from thread::spawn
to guarantee the thread is run to completion
Calling join
on the handle blocks the thread currently running until the thread represented by the handle terminates. Blocking a thread means that thread is prevented from performing work or exiting. Because we’ve put the call to join
after the main thread’s for
loop, running Listing 16-2 should produce output similar to this:
hi number 1 from the main thread!
hi number 2 from the main thread!
hi number 1 from the spawned thread!
hi number 3 from the main thread!
hi number 2 from the spawned thread!
hi number 4 from the main thread!
hi number 3 from the spawned thread!
hi number 4 from the spawned thread!
hi number 5 from the spawned thread!
hi number 7 from the spawned thread!
hi number 8 from the spawned thread!
hi number 9 from the spawned thread!
The two threads continue alternating, but the main thread waits because of the call to and does not end until the spawned thread is finished.
But let’s see what happens when we instead move handle.join()
before the for
loop in main
, like this:
Filename: src/main.rs
The main thread will wait for the spawned thread to finish and then run its for
loop, so the output won’t be interleaved anymore, as shown here:
hi number 1 from the spawned thread!
hi number 2 from the spawned thread!
hi number 3 from the spawned thread!
hi number 4 from the spawned thread!
hi number 5 from the spawned thread!
hi number 6 from the spawned thread!
hi number 7 from the spawned thread!
hi number 8 from the spawned thread!
hi number 9 from the spawned thread!
hi number 1 from the main thread!
hi number 2 from the main thread!
hi number 3 from the main thread!
hi number 4 from the main thread!
Small details, such as where join
is called, can affect whether or not your threads run at the same time.
We'll often use the move
keyword with closures passed to thread::spawn
because the closure will then take ownership of the values it uses from the environment, thus transferring ownership of those values from one thread to another. In the section of Chapter 13, we discussed move
in the context of closures. Now, we’ll concentrate more on the interaction between move
and thread::spawn
.
Notice in Listing 16-1 that the closure we pass to thread::spawn
takes no arguments: we’re not using any data from the main thread in the spawned thread’s code. To use data from the main thread in the spawned thread, the spawned thread’s closure must capture the values it needs. Listing 16-3 shows an attempt to create a vector in the main thread and use it in the spawned thread. However, this won’t yet work, as you’ll see in a moment.
Filename: src/main.rs
use std::thread;
fn main() {
let v = vec![1, 2, 3];
let handle = thread::spawn(|| {
println!("Here's a vector: {:?}", v);
});
handle.join().unwrap();
}
Listing 16-3: Attempting to use a vector created by the main thread in another thread
$ cargo run
Compiling threads v0.1.0 (file:///projects/threads)
error[E0373]: closure may outlive the current function, but it borrows `v`, which is owned by the current function
--> src/main.rs:6:32
|
6 | let handle = thread::spawn(|| {
| ^^ may outlive borrowed value `v`
7 | println!("Here's a vector: {:?}", v);
| - `v` is borrowed here
|
note: function requires argument type to outlive `'static`
--> src/main.rs:6:18
|
6 | let handle = thread::spawn(|| {
| __________________^
8 | | });
| |______^
help: to force the closure to take ownership of `v` (and any other referenced variables), use the `move` keyword
|
| ++++
For more information about this error, try `rustc --explain E0373`.
error: could not compile `threads` due to previous error
Rust infers how to capture v
, and because println!
only needs a reference to v
, the closure tries to borrow v
. However, there’s a problem: Rust can’t tell how long the spawned thread will run, so it doesn’t know if the reference to v
will always be valid.
Listing 16-4 provides a scenario that’s more likely to have a reference to v
that won’t be valid:
Filename: src/main.rs
Listing 16-4: A thread with a closure that attempts to capture a reference to v
from a main thread that drops v
If Rust allowed us to run this code, there’s a possibility the spawned thread would be immediately put in the background without running at all. The spawned thread has a reference to v
inside, but the main thread immediately drops v
, using the drop
function we discussed in Chapter 15. Then, when the spawned thread starts to execute, v
is no longer valid, so a reference to it is also invalid. Oh no!
To fix the compiler error in Listing 16-3, we can use the error message’s advice:
help: to force the closure to take ownership of `v` (and any other referenced variables), use the `move` keyword
|
6 | let handle = thread::spawn(move || {
| ++++
By adding the move
keyword before the closure, we force the closure to take ownership of the values it’s using rather than allowing Rust to infer that it should borrow the values. The modification to Listing 16-3 shown in Listing 16-5 will compile and run as we intend:
Filename: src/main.rs
use std::thread;
fn main() {
let v = vec![1, 2, 3];
let handle = thread::spawn(move || {
println!("Here's a vector: {:?}", v);
});
handle.join().unwrap();
}
Listing 16-5: Using the move
keyword to force a closure to take ownership of the values it uses
We might be tempted to try the same thing to fix the code in Listing 16-4 where the main thread called drop
by using a move
closure. However, this fix will not work because what Listing 16-4 is trying to do is disallowed for a different reason. If we added move
to the closure, we would move v
into the closure’s environment, and we could no longer call drop
on it in the main thread. We would get this compiler error instead:
$ cargo run
Compiling threads v0.1.0 (file:///projects/threads)
error[E0382]: use of moved value: `v`
--> src/main.rs:10:10
|
4 | let v = vec![1, 2, 3];
| - move occurs because `v` has type `Vec<i32>`, which does not implement the `Copy` trait
5 |
6 | let handle = thread::spawn(move || {
| ------- value moved into closure here
7 | println!("Here's a vector: {:?}", v);
| - variable moved due to use in closure
...
10 | drop(v); // oh no!
| ^ value used here after move
For more information about this error, try `rustc --explain E0382`.
error: could not compile `threads` due to previous error
Rust’s ownership rules have saved us again! We got an error from the code in Listing 16-3 because Rust was being conservative and only borrowing v
for the thread, which meant the main thread could theoretically invalidate the spawned thread’s reference. By telling Rust to move ownership of v
to the spawned thread, we’re guaranteeing Rust that the main thread won’t use v
anymore. If we change Listing 16-4 in the same way, we’re then violating the ownership rules when we try to use v
in the main thread. The keyword overrides Rust’s conservative default of borrowing; it doesn’t let us violate the ownership rules.