当 $haystack
并非仅包含类型为 $type
的变量时报告错误,错误讯息由 $message
指定。
assertNotContainsOnly()
是与之相反的断言,并接受相同的参数。
例 A.8: assertContainsOnly() 的用法
- PHPUnit 6.5.0 by Sebastian Bergmann and contributors.
- F
- Time: 0 seconds, Memory: 5.00Mb
- There was 1 failure:
- 1) ContainsOnlyTest::testFailure
- Failed asserting that Array (
- 0 => '1'
- 2 => 3
- ) contains only values of type "string".
- /home/sb/ContainsOnlyTest.php:6
- Tests: 1, Assertions: 1, Failures: 1.